6p^2-7p-1=0

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Solution for 6p^2-7p-1=0 equation: 



6p^2-7p-1=0

a = 6; b = -7; c = -1;
Δ = b2-4ac
Δ = -72-4·6·(-1)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{73}}{2*6}=\frac{7-\sqrt{73}}{12}
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{73}}{2*6}=\frac{7+\sqrt{73}}{12}
$

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